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Meeting Rooms
Given an array of meeting time intervals intervals where intervals[i] = [start_i, end_i], determine if a person could attend all meetings.
Two meetings that share only an endpoint (one ends exactly when the next begins) do not count as a conflict.
Examples
Constraints
- 0 <= intervals.length <= 10^4
- intervals[i].length == 2
- 0 <= start_i < end_i <= 10^6
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Your approach
- Pattern:Intervals
- Time:O(N)
- Space:O(1)
Complete approach — pattern and complexity both named.
Coach
What you got right
You correctly matched the sorted input requirement and implemented a linear-time scan using two pointers.
Where it diverged
No divergence detected. The code correctly aligns with the stated approach.
Next attempt: focus on
Try solving related sliding window problems to build familiarity with two-pointer variants.
Signals
No signals fired — clean run, you stayed in flow.